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8x^2+5x=400
We move all terms to the left:
8x^2+5x-(400)=0
a = 8; b = 5; c = -400;
Δ = b2-4ac
Δ = 52-4·8·(-400)
Δ = 12825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12825}=\sqrt{225*57}=\sqrt{225}*\sqrt{57}=15\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-15\sqrt{57}}{2*8}=\frac{-5-15\sqrt{57}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+15\sqrt{57}}{2*8}=\frac{-5+15\sqrt{57}}{16} $
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